How To Find the Circumcenter, the Center of the Circumscribed Circle of a Triangle
Learn to find the circumcircle, the center of the circle circumscribed of a triangle. Perpendicular bisectors of the sides
The perpendicular bisectors of the triangle's sides. The circumcircle's center
The perpendicular bisector of a segment
- The perpendicular bisector of a segment is the line perpendicular to the segment, that passes through the middle of it.
- Important: Any point belonging to the perpendicular bisector is equidistant from the ends of the segment.
The perpendicular bisectors of triangle's sides
- In any triangle the perpendicular bisectors of the sides are concurrent in a point which is the center of the circle passing through the vertices of the triangle, called the circumscribed circle of the triangle (the circumcircle).
The perpendicular bisectors and the center of the circumcircle
- In the triangle △ABC, OM1 is the perpendicular bisector of segment BC =>
BM1 = CM1 = BC / 2 = a / 2. The length of segment BC = a. - OM2 is the perpendicular bisector of segment AC =>
AM2 = CM2 = AC / 2 = b / 2. The length of segment AC = b. - OM3 is the perpendicular bisector of segment AB =>
AM3 = BM3 = AB / 2 = c / 2. The length of segment AB = c.
- The perpendicular bisectors OM1, OM2 and OM3 intersect at point O, which is the center of the circumscribed circle of the triangle.
Why are the perpendicular bisectors concurrent in the center of the circumscribed circle?
- O is a point on the perpendicular bisector OM1 => BM1 = CM1 = a/2; OM1 ⊥ BC (⊥ is the symbol for segments or perpendicular lines); and OM1 is a common segment => the right triangles △OBM1 ≅ △OCM1 => OB ≅ OC.
- O is a point on the perpendicular bisector OM2 => AM2 = CM2 = b/2; OM2 ⊥ AC; and OM2 is a common segment => the right triangles △OAM2 ≅ △OCM2 => OA ≅ OC.
- From the relations above, it follows that OA = OB = OC = R, where R is the radius of the circumscribed circle of the triangle.